Why is `True is False == False`, False in Python? -

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• why (1 in [1,0] == true) evaluate false? [duplicate] 1 answer

why these statements work expected when brackets used:

>>> (true false) == false true  >>> true (false == false) true 

but returns false when there no brackets?

>>> true false == false false 

based on python documentation operator precedence :

note comparisons, membership tests, , identity tests, have same precedence , have left-to-right chaining feature described in comparisons section.

so have chained statement following :

>>> (true false) , (false==false) false 

you can assume central object shared between 2 operations , other objects (false in case).

and note true comparisons, including membership tests , identity tests operations following operands :

in, not in, is, not, <, <=, >, >=, !=, == 

example :

>>> 1 in [1,2] == true false