lambda - Java 8 Streams: Analyze same list elements -


code explains better:

test case

@org.junit.test public void test() {     list<integer> values = arrays.aslist(1, 2, 3, 4, 5, 6, 7, 8, 9);      system.out.println(withoutstreams(values)); // output: 1,9     system.out.println(withstreamsol1error(values)); // compile time error     system.out.println(withstreamsol2(values)); // output: 1,9 } 

required solution (without stream):

private list<integer> withoutstreams(list<integer> values) {     // list<integer> values = arrays.aslist(1, 2, 3, 4, 5, 6, 7, 8, 9);      (int index1 = 0; index1 < values.size(); index1++) {         int value1 = values.get(index1);         if (value1 == 10)             return arrays.aslist(value1);         (int index2 = index1 + 1; index2 < values.size(); index2++) {             int value2 = values.get(index2);              if ((value1 + value2) == 10) {                 return arrays.aslist(value1, value2);             }         }     }      return collections.emptylist(); } 

my attempt : stream: (compile time error - mismatch)

private list<integer> withstreamsol1error(list<integer> values) {     list<integer> exactequal = values.stream().filter(value -> value.intvalue() == 10).limit(1)             .collect(collectors.tolist());      // compile time error     if (exactequal.isempty()) {         intstream.range(0, values.size() - 1)                 .foreachordered(index -> intstream.range(index + 1, values.size() - 1)                         .filter(index2 -> values.get(index) + values.get(index2) == 10).limit(1)                         .collect(collectors.tolist()));     }      return collections.emptylist(); } 

with stream (working)

private list<integer> withstreamsol2(list<integer> values) {     list<integer> exactequal = values.stream().filter(value -> value.intvalue() == 10).limit(1)             .collect(collectors.tolist());      int index1 = 0;     final list<integer> result = new arraylist<>();     if (exactequal.isempty()) {         values.stream().foreach(value1 -> {             if(!result.isempty()) // query: how can stop outer foreach                 return;              result.add(value1);             result.addall(values.stream().skip(index1).filter(value2 -> (value1 + value2) == 10).limit(1)                     .collect(collectors.tolist()));         });     }      return result; } 

can suggest solution problem?

private static list<integer> withstreamsol1(list<integer> values) {     list<integer> result = new arraylist<>();     values.stream()         .filter(i -> result.isempty() && == 10)         .foreach(i -> result.add(i));     intstream.range(0, values.size())         .filter(i -> result.isempty())         .foreach(i -> intstream.range(i + 1, values.size())             .filter(j -> result.isempty() && values.get(i) + values.get(j) == 10)             .foreach(j -> result.addall(arrays.aslist(values.get(i), values.get(j)))));     return result; } 

or

private static stream<int[]> streamofoneortwoelements(list<integer> list) {     return stream.concat(         list.stream()             .map(i -> new int[] {i}),         intstream.range(0, list.size())             .boxed()             .flatmap(i -> intstream.range(i + 1, list.size())                 .maptoobj(j -> new int[] {list.get(i), list.get(j)}))); }  private static list<integer> withstreamsol3(list<integer> values) {     optional<int[]> array = streamofoneortwoelements(values)         .filter(a -> intstream.of(a).sum() == 10)         .findfirst();     return array.ispresent()         ? intstream.of(array.get()).boxed().collect(collectors.tolist())         : collections.emptylist(); } 

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