c - I wonder whats happens when if(i%2) what does it checks to come to continue. It misses == but it prints out the sum as 20? Why? -


#import <stdio.h> int main(void) {     int sum,i;     sum = 0;     for(i=0;i<10;i++) {         if(i%2)             continue;         sum+=i;     }     printf("\n%d",sum);     return 0; } 

how if(i%2) works in above code?

in computing, modulo operation finds remainder after division of 1 number (sometimes called modulus).% modulus operator.

so i%2 returns remainder left after divided 2.
therefore if odd i%2=1(true)
else 0(false).(even condition)

therefore if added sum else loop continues.


Comments

Popular posts from this blog

java - Andrioid studio start fail: Fatal error initializing 'null' -

android - Gradle sync Error:Configuration with name 'default' not found -

StringGrid issue in Delphi XE8 firemonkey mobile app -