command line - GO: {GOOS} and {GOARCH} not recognised in environment -

-

i want change diretory go/pkg/darwin_amd64 $ cd $gopath/pkg/${goos}_${goarch} doesn't find folder though directory exists.

$ echo $gopath/pkg/${goos}_${goarch} gives /go/pkg/_ instead of /go/pkg/darwin_amd64.

$ go env prints: 

goarch="amd64" gobin="" gochar="6" goexe="" gohostarch="amd64" gohostos="darwin" goos="darwin" gopath="/users/sahilkapoor/go" gorace="" goroot="/usr/local/go" gotooldir="/usr/local/go/pkg/tool/darwin_amd64" cc="clang" gogccflags="-fpic -m64 -pthread -fno-caret-diagnostics -qunused-arguments -fmessage-length=0 -fno-common" cxx="clang++" cgo_enabled="1"

we can see goos , goarch defined here. using terminal on mac osx 10.10.3. missing?

$goos , $goarch defined in shell if have exported them (which, unless doing cross compilation, unlikely).

when run go env, default values shown when have not been overwritten environment. should change command following desired results:

cd $(go env gopath)/pkg/$(go env goos)_$(go env goarch)

Comments

Post a Comment

Popular posts from this blog

how to do line continuation in perl debugger for entering raw multi-line text (EOT)? -

-
i learning perl. trying in debugger define variable, here-document. not know how enter same code in perl script, in debugger. due new lines present inside eot, makes hard in interactive debugger. here small example. have script: >cat ex1.perl #!/usr/bin/perl -w $s =<<'eot'; first line second line eot print $s now run , gives expected output: >perl ex1.perl first line second line now want same in debugger. tried this: >perl -de0 loading db routines perl5db.pl version 1.39_10 db<1> $s =<<'eot';\ cont: first line\ cont: second line\ cont: eot can't find string terminator "eot" anywhere before eof @ (eval 6) [/usr/share/perl/5.18/perl5db.pl:732] line 2. @ (eval 6)[/usr/share/perl/5.18/perl5db.pl:732] line 2. eval 'no strict; ($@, $!, $^e, $,, $/, $\\, $^w) = @db::saved;package main; $^d = $^d | $db::db_stop; $s =<<\'eot\'; first line second line eot; ' called @ /usr/share/perl...
Read more

javascript - Create websocket without connecting -

-
is there way create websocket without connecting right away? far think var ws = new websocket("ws://ws.my.url.com"); creates , connects right away. i'd create socket, define callbacks, , connect once user clicks connect button. thanks no. creating websocket means you've created connection server (or started process of connecting). there no such thing creating websocket isn't connecting yet. you create object store configuration parameters , tell object connect when wanted to, though i'm not sure why that's better creating actual websocket when connect made. or create function setup work , call function later when user clicks connect button.
Read more

sharepoint - Accessing files across a shared directory using a Windows service -

-
i trying access files on shared directory (sharepoint): \\sitename\sites\path_to_doc\doc.csv so have custom application looks @ files on shared drive , when launch application going folder it's installed - c:\myapp.exe, the application can access them . when corresponding service launched services.msc same user launched executable in previous step, doesn't find files on shared directory. i guess, question is: what general differences launching application interactively double clicking versus launching executable using service , of respect windows permissions , remote shared folders?
Read more