How can I compare more than 2 condition in python -

angle1 = int(input('please enter 1st angle:')) angle2 = int(input('please enter 2nd angle:')) angle3 = int(input('please enter 3rd angle:')) angle = angle1 + angle2 + angle3 while angle == 180:     if angle1 , angle2 , angle3 < 90:         print ('this actue triangle')      elif angle1 or angle2 or angle3 == 90:         print ('this right triangle')      elif angle1 or angle2 or angle3 > 90:          print ('this obtuse triangle')      angle = angle1 + angle2 + angle3         angle1 = int(input('please enter 1st angle:'))     angle2 = int(input('please enter 2nd angle:'))     angle3 = int(input('please enter 3rd angle:')) 

i tried compare each angle condition seem whenever enter number in angle3, compare condition , ignore other 2 angle. please me this!

you can use any , all functions.

ask = lambda: [int(input('please enter {0}st angle:'.format(i))) in range(1,4)] angles = ask() while sum(angles) == 180:     if all(a < 90 in angles):         print ('this actue triangle')      elif any(a == 90 in angles):         print ('this right triangle')      elif any(a > 90 in angles):         print ('this obtuse triangle')      angles = ask() 

edit: comments python beginners:

first line, used lambda expression one-line function. in lambda expression, used list comprehension (a compact way build list).

so ask() returns list containing 3 angles e.g. [90, 45, 45].

you can find information sum(), any() , all() here.