state - Converting Epsilon-NFA to NFA -

i'm having trouble understanding process of converting epsilon-nfa nfa, wondered if me it:

and answer says:

the 0 in new nfa has going 1,2 , 2. figured because 0 in epsilon nfa leads 1 , 2 (combined epsilon). why doesn't 1,2 have a-step going 2, because in epsilon nfa 1 has a-step 1 , 2?

whenever remove ε nfa, should careful @ time of conversion direction of ε transition.

in case, ε transition node 1 node 2, accept state. so, need consider incoming transitions state 1.

also, {1} moves {2} upon ε-transition, 1 can reduced {1,2} , it'll accept state. check this question know why happens.

so, removal of ε-transition, check incoming transitions state 1, replace {1} accept state {1,2} , convert them :-

1. state 0 transits state 1 when reads a, , state 1 automatically transit state 2 reads ε.

so, should omit path 1 2(of ε-transition), , state 0 on reading transits both {1} , {2}. so, 1 transition added exisitng nfa

{0} -> {2} (on reading a)    // should drawn, not given {0} -> {1} (on reading a)    // given 

2. state 2 transits state 1 when reads a, , state 1 automatically transit state 2 reads ε.

so, should omit path 1 2(of ε-transition), , state 2 on reading transits both {1} , {2}, itself. so, 1 transition added exisitng nfa

{2} -> {2} (on reading a)    // self-loop, should drawn, not given {2} -> {1} (on reading a)    // given 

please take special care replace state {1} accept state {1,2} because of reason explained above.

there no more incoming arrows directed state 1 , hence dependencies resolved. new nfa matches given nfa answer.