PHP-Login.net Advanced Script - how to allow logged in users access to other pages/"views"? -

i using php-login.net advanced script , see how when user logs in, goes logged_in view.

however, want user able go php page, want visible if logged in.

not sure if "view" of index.php or own page?

how make work? thanks!

 <?php  /**  * simple php login script / advanced version  * more versions (one-file, minimal, framework-like) visit http://www.php-login.net  *  * @author panique  * @link http://www.php-login[dot]net  */  // check minimum php version if (version_compare(php_version, '5.3.7', '<')) {     exit('sorry, script not run on php version smaller 5.3.7 !'); } else if (version_compare(php_version, '5.5.0', '<')) {     // if using php 5.3 or php 5.4 have include password_api_compatibility_library.php     // (this library adds php 5.5 password hashing functions older versions of php)     require_once('libraries/password_compatibility_library.php'); } // include config require_once('config/config.php');  // include to-be-used language, english default. feel free translate project , include else require_once('translations/en.php');  // include phpmailer library require_once('libraries/phpmailer.php');  // load login class require_once('classes/login.php');  // create login object. when object created, login/logout stuff automatically // single line handles entire login process. $login = new login();  // ... ask if logged in here: if ($login->isuserloggedin() == true) {     // user logged in. can whatever want here.     // demonstration purposes, show "you logged in" view.     include("views/logged_in.php");  } else {     // user not logged in. can whatever want here.     // demonstration purposes, show "you not logged in" view.     include("views/not_logged_in.php"); }  ?> 

i think if reuse code on second logged in page, work - if logged in = true, display page, if not true, display view of log in page.

so example, lets second "logged in only" page index2.php, have

 <?php   if ($login->isuserloggedin() == true) {     // user logged in, display page       include("views/index2.php");  } else {     // user not logged in  view.     include("views/not_logged_in.php"); } ?> 

okay looks using "index2.php" page, creates new session because have log in , out 2x ....

if click logout, shows login screen, if go "index2.php" directly, shows still logged in

this not correct solution ....